Most people solve their first Starlock grid in four or five minutes and assume the way to get faster is to think faster. It is not. Fast solvers are not thinking harder — they are using a small set of deductions that turn most of the grid into forced moves. Here they are, roughly in the order you should reach for them.
Mark before you place
The single biggest time sink is placing a star, discovering a conflict eight moves later, and having to unwind. The ✕ mark exists to prevent that. Before you place anything, sweep the board and eliminate the cells that obviously cannot hold a star. Every mark you make is a deduction you will not have to re-derive.
The habit that costs the most time is treating marks as optional because "I can see it". On an 8×8 grid there are sixty-four cells and eight simultaneous constraints. Nobody holds that.
Start with the smallest region
A region of three or four cells is a gift: it must contain a star, so the star is in one of very few places, and every row and column those cells occupy is heavily constrained. Look for the smallest region on the board and work outward from it. Large sprawling regions tell you almost nothing early on and are usually the last thing you resolve.
Fast solvers are not thinking harder. They are using deductions that turn most of the grid into forced moves.
The single-row region
If every cell of a region sits within one row, then that row's star is inside that region — which means every other cell in that row is dead, and can be marked immediately. The same applies to a region confined to a single column. This one deduction often clears a fifth of the board in a couple of seconds, and it is the most commonly missed pattern by new players.
The exclusion counterpart
The reverse is just as powerful. If a region is entirely contained within two rows, then those two rows contain that region's star, and no other region confined to those same two rows can also claim them. Counting regions against rows — "these three regions live entirely inside these three rows" — is how experienced solvers crack the middle of a hard grid without any trial and error.
The adjacency squeeze
The no-touching rule is a constraint on pairs of adjacent rows, and it is far stronger than it looks. If row 4's star is in column 6, then row 3 and row 5 cannot use columns 5, 6 or 7. On a narrow board, placing one star can eliminate three columns from each neighbouring row at once. When you place a star, immediately mark the six cells around it. Always. It takes two seconds and it routinely cascades.
Work the corners
Corner and edge cells have fewer neighbours, so they are less constrained by adjacency — which sounds like a disadvantage but means they are often where a forced star hides. When the middle of the board has gone quiet and nothing is forced, check whether a region's only remaining cells are pinned against an edge.
Do not solve rows in order
Reading the board top to bottom feels natural and is almost always slower. The grid does not care about order. Solve the most constrained thing available at any moment, wherever it is — the small region, the pinned column, the row with only two live cells left. Fast solves look chaotic from the outside.
On par, and on being beaten
Par is not the average human time; it is derived from how much backtracking the solver needed on that specific grid. A grid where every step is forced has a tight par even if it looks intimidating. A grid with one genuinely hard deduction in the middle gets a generous one. If you are consistently beating par, move up to 9×9 or 10×10 in unlimited mode — the techniques above scale, but the exclusion counting in step 4 gets much more valuable as the board grows.
And if somebody sends you a challenge link and beats you by forty seconds, the difference is almost never raw intelligence. It is step 3.
The short version
Marks before stars, smallest regions first, and the two-row squeeze — the handful of techniques that separate a five-minute solve from a ninety-second one.